Chuyển đổi thử nghiệm (Try Conversions)
The effective expansion of ? is a little more complicated than previously indicated:
expression?
works the same as
match expression {
Ok(value) => value,
Err(err) => return Err(From::from(err)),
}
The From::from call here means we attempt to convert the error type to the type returned by the function. This makes it easy to encapsulate errors into higher-level errors.
Example
use std::error::Error; use std::fmt::{self, Display, Formatter}; use std::fs::File; use std::io::{self, Read}; #[derive(Debug)] enum ReadUsernameError { IoError(io::Error), EmptyUsername(String), } impl Error for ReadUsernameError {} impl Display for ReadUsernameError { fn fmt(&self, f: &mut Formatter) -> fmt::Result { match self { Self::IoError(e) => write!(f, "IO error: {e}"), Self::EmptyUsername(path) => write!(f, "Found no username in {path}"), } } } impl From<io::Error> for ReadUsernameError { fn from(err: io::Error) -> Self { Self::IoError(err) } } fn read_username(path: &str) -> Result<String, ReadUsernameError> { let mut username = String::with_capacity(100); File::open(path)?.read_to_string(&mut username)?; if username.is_empty() { return Err(ReadUsernameError::EmptyUsername(String::from(path))); } Ok(username) } fn main() { //std::fs::write("config.dat", "").unwrap(); let username = read_username("config.dat"); println!("username or error: {username:?}"); }
The ? operator must return a value compatible with the return type of the function. For Result, it means that the error types have to be compatible. A function that returns Result<T, ErrorOuter> can only use ? on a value of type Result<U, ErrorInner> if ErrorOuter and ErrorInner are the same type or if ErrorOuter implements From<ErrorInner>.
A common alternative to a From implementation is Result::map_err, especially when the conversion only happens in one place.
There is no compatibility requirement for Option. A function returning Option<T> can use the ? operator on Option<U> for arbitrary T and U types.
A function that returns Result cannot use ? on Option and vice versa. However, Option::ok_or converts Option to Result whereas Result::ok turns Result into Option.